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How much does a Product development engineer make in Florida?
$100,000
/ Annual
Based on 154 salaries
The average product development engineer salary in Florida is $100,000 per year or $48.08 per hour. Entry level positions start at $80,000 per year while most experienced workers make up to $126,540 per year.
Median
$100,000
chart
Low
$80,000
High
$126,540

Average salaries by state

Washington
$151,042
Based on 472 salaries
Texas
$130,000
Based on 490 salaries
California
$130,000
Based on 1964 salaries
New Mexico
$126,550
Based on 63 salaries
Missouri
$125,000
Based on 178 salaries
Delaware
$117,500
Based on 22 salaries
Rhode Island
$114,400
Based on 28 salaries
Virginia
$114,021
Based on 117 salaries
Georgia
$110,000
Based on 285 salaries
Minnesota
$110,000
Based on 332 salaries
Oregon
$109,325
Based on 111 salaries
Maryland
$108,583
Based on 71 salaries
Maine
$105,000
Based on 17 salaries
Kansas
$105,000
Based on 57 salaries
North Carolina
$105,000
Based on 197 salaries
Michigan
$105,000
Based on 494 salaries
Massachusetts
$101,920
Based on 429 salaries
Iowa
$101,250
Based on 95 salaries
Colorado
$100,683
Based on 552 salaries
Pennsylvania
$100,000
Based on 337 salaries
Wisconsin
$98,000
Based on 249 salaries
Tennessee
$98,000
Based on 274 salaries
Ohio
$97,500
Based on 297 salaries
Alabama
$96,250
Based on 26 salaries
Arizona
$96,000
Based on 251 salaries
Mississippi
$95,275
Based on 26 salaries
Connecticut
$95,000
Based on 134 salaries
New York
$95,000
Based on 526 salaries
New Jersey
$93,800
Based on 454 salaries
Illinois
$92,560
Based on 315 salaries
Indiana
$91,250
Based on 158 salaries
Nevada
$90,000
Based on 29 salaries
South Carolina
$87,500
Based on 27 salaries
Utah
$85,400
Based on 100 salaries
Kentucky
$79,000
Based on 55 salaries
Arkansas
$75,588
Based on 18 salaries
New Hampshire
$70,000
Based on 74 salaries

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